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Differential Equations

MHT CET 2025 19th April Morning Shift

MCQ+2 / -02025
The solution of the differential equation $x \frac{\mathrm{~d}^2 y}{\mathrm{~d} x^2}=1$ at $x=y=1$ with $\frac{\mathrm{d} y}{\mathrm{~d} x}=0$ at $x=1$, is

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