Mht Cet
Differential Equations
MHT CET 2025 19th April Morning Shift
MCQ+2 / -02025
The solution of the differential equation $x \frac{\mathrm{~d}^2 y}{\mathrm{~d} x^2}=1$ at $x=y=1$ with $\frac{\mathrm{d} y}{\mathrm{~d} x}=0$ at $x=1$, is
Mht Cet
MHT CET 2025 19th April Morning Shift