Mht CetMathematical ReasoningMHT CET 2024 4th May Evening ShiftMCQ+2 / -02024The converse of $[p \wedge(\sim q)] \rightarrow r$ isA $\sim \mathrm{r} \rightarrow(\sim \mathrm{p} \vee \mathrm{q})$B $\mathrm{r} \rightarrow(\sim \mathrm{p} \wedge \sim \mathrm{q})$C $(\sim p \vee q) \rightarrow \sim r$D\({r \rightarrow (p \wedge \sim q)}\)Check AnswerClear SelectionReveal AnswerShow Explanation
