Limits Continuity And Differentiability

If the function $\mathrm{f}(x)=\left(\frac{5 x-8}{8-3 x}\right)^{\frac{3}{2 x-4}}$ if $x \neq 2$.
$=\mathrm{k}$
if $x=2$.
is continuous at $x=2$, then $\mathrm{k}=$