Mht Cet
Limits Continuity And Differentiability
MHT CET 2024 2nd May Morning Shift
MCQ+2 / -02024
If $\mathrm{f}(x)=\frac{1+\cos \pi x}{\pi(1-x)^2}$, for $x \neq 1$ is continuous at $x=1$, then $\mathrm{f}(1)$ is equal to
Mht Cet
MHT CET 2024 2nd May Morning Shift
If $\mathrm{f}(x)=\frac{1+\cos \pi x}{\pi(1-x)^2}$, for $x \neq 1$ is continuous at $x=1$, then $\mathrm{f}(1)$ is equal to