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Limits Continuity And Differentiability

MHT CET 2024 2nd May Morning Shift

MCQ+2 / -02024

If $\mathrm{f}(x)=\frac{1+\cos \pi x}{\pi(1-x)^2}$, for $x \neq 1$ is continuous at $x=1$, then $\mathrm{f}(1)$ is equal to

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