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Inverse Trigonometric Functions

MHT CET 2024 16th May Evening Shift

MCQ+2 / -02024

If $y=\tan ^{-1}\left(\frac{2+3 x}{3-2 x}\right)+\tan ^{-1}\left(\frac{4 x}{1+5 x^2}\right)$, then $\frac{d y}{d x}=$

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