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Inverse Trigonometric Functions

MHT CET 2024 15th May Evening Shift

MCQ+2 / -02024

If $0< x<1$, then $\sqrt{1+x^2}\left[\left\{x \cos \left(\cot ^{-1} x\right)+\sin \left(\cot ^{-1} x\right)\right\}^2-1\right]^{\frac{1}{2}}$ is equal to

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