Mht CetIndefinite IntegrationMHT CET 2024 2nd May Morning ShiftMCQ+2 / -02024\(\int \log (1+x)^{1+x} \mathrm{~d} x=\)A $(1+x)^2 \log (1+x)-\frac{1}{2}+\mathrm{c}$, where c is a constant of integration.B $\frac{(1+x)^2}{2} \log (1+x)+\mathrm{c}$, where c is a constant of integration.C $\frac{(1+x)^2}{2}\left[\log (1+x)-\frac{1}{2}\right]+\mathrm{c}$, where c is a constant of integration.D $\frac{1+x}{2} \log (1+x)+\mathrm{c}$, where c is a constant of integration.Check AnswerClear SelectionReveal AnswerShow Explanation
