Mht CetIndefinite IntegrationMHT CET 2024 2nd May Morning ShiftMCQ+2 / -02024\(\int 3^{3^x} \cdot 3^x d x=\)A $\frac{3^x}{(\log 3)^2}+c$, where $c$ is a constant of integration.B $\frac{3^{3^x}}{\log 3}+\mathrm{c}$, where c is a constant of integration.C $\frac{3^{3^x}}{(\log 3)^2}+c$, where $c$ is a constant of integration.D $\frac{3^x}{\log 3}+\mathrm{c}$, where c is a constant of integration.Check AnswerClear SelectionReveal AnswerShow Explanation
