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Motion

MHT CET 2023 12th May Evening Shift

MCQ+1 / -02023

A ball is projected vertically upwards from ground. It reaches a height '\(h\)' in time \(t_1\), continues its motion and then takes a time \(t_2\) to reach ground. The height $h$ in terms of \(g, t_1\) and \(\mathrm{t}_2\) is \((\mathrm{g}=\) acceleration due to gravity)

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