Mht CetMotionMHT CET 2026 18th April Evening ShiftMCQ+1 / -02026For a projectile motion, the range R is 'n' times the maximum height H. So the angle of projection isA$\sin^{-1}\left(\dfrac{2}{n}\right)$B$\cos^{-1}\left(\dfrac{4}{n}\right)$C$\tan^{-1}\left(\dfrac{4}{n}\right)$D$\tan^{-1}\left(\dfrac{2}{n}\right)$Check AnswerClear SelectionReveal AnswerShow Explanation
