Mht CetFunctionsMHT CET 2023 14th May Morning ShiftMCQ+2 / -02023The range of the function \(\mathrm{f}(x)=\frac{x^2}{x^2+1}\) isA\((0,1)\)B\([0,1)\)C\((0,1]\)D\([0,1]\)Check AnswerClear SelectionReveal AnswerShow Explanation