Mht CetFunctionsMHT CET 2026 20th April Evening ShiftMCQ+2 / -02026If $f(x) = \dfrac{2x - 1}{x + 5}$, $x \neq -5$ then $f^{-1}(x)$ is equal toA$\dfrac{x + 5}{2x - 1}$, $x \neq \dfrac{1}{2}$B$\dfrac{5x + 1}{2 - x}$, $x \neq 2$C$\dfrac{5x - 1}{2 - x}$, $x \neq 2$D$\dfrac{x - 5}{2x + 1}$, $x \neq -\dfrac{1}{2}$Check AnswerClear SelectionReveal AnswerShow Explanation
