Mht CetDifferentiationMHT CET 2021 20th September Evening ShiftMCQ+2 / -02021\(y=\sqrt{e^{\sqrt{x}}}\), then \(\frac{d y}{d x}=\)A\(\frac{e^{\sqrt{x}}}{4 \sqrt{x}}\)B\(\frac{\mathrm{e}^{\sqrt{x}}}{4 x}\)C\(\frac{e^{\frac{\sqrt{x}}{2}}}{4 \sqrt{x}}\)D\(\frac{e^{\sqrt{x}}}{2 \sqrt{x}}\)Check AnswerClear SelectionReveal AnswerShow Explanation
