Mht Cet
Differentiation
MHT CET 2020 19th October Evening Shift
MCQ+2 / -02020
If $x^2 y^2=\sin ^{-1} \sqrt{x^2+y^2}+\cos ^{-1} \sqrt{x^2+y^2}$ then $\frac{d y}{d x}=$
Mht Cet
MHT CET 2020 19th October Evening Shift
If $x^2 y^2=\sin ^{-1} \sqrt{x^2+y^2}+\cos ^{-1} \sqrt{x^2+y^2}$ then $\frac{d y}{d x}=$