Mht Cet
Matrices And Determinants
MHT CET 2020 16th October Evening Shift
MCQ+2 / -02020
If $$A=\left[\begin{array}{ll}2 & 3 \\ 1 & 2\end{array}\right], \quad B=\left[\begin{array}{ll}1 & 0 \\ 3 & 1\end{array}\right]$$, then \(B^{-1} A^{-1}=\)
Mht Cet
MHT CET 2020 16th October Evening Shift
If $$A=\left[\begin{array}{ll}2 & 3 \\ 1 & 2\end{array}\right], \quad B=\left[\begin{array}{ll}1 & 0 \\ 3 & 1\end{array}\right]$$, then \(B^{-1} A^{-1}=\)