Mht CetMatrices And DeterminantsMHT CET 2026 20th April Evening ShiftMCQ+2 / -02026If $A = \begin{bmatrix} 1 & -5 \\ -2 & 4 \end{bmatrix}$, then $A^{-1} =$A$-\dfrac{1}{6}\begin{bmatrix} -4 & 5 \\ 2 & -1 \end{bmatrix}$B$\dfrac{1}{14}\begin{bmatrix} -1 & 5 \\ 2 & -4 \end{bmatrix}$C$\dfrac{1}{14}\begin{bmatrix} 4 & 5 \\ 2 & 1 \end{bmatrix}$D$-\dfrac{1}{6}\begin{bmatrix} 4 & 5 \\ 2 & 1 \end{bmatrix}$Check AnswerClear SelectionReveal AnswerShow Explanation
