Mht Cet
Matrices And Determinants
MHT CET 2019 2nd May Morning Shift
MCQ+2 / -02019
If $A=\left[\begin{array}{ll}x & 1 \\ 1 & 0\end{array}\right]$ and $A=A^{-1}$, then $x=\ldots \ldots$
Mht Cet
MHT CET 2019 2nd May Morning Shift
If $A=\left[\begin{array}{ll}x & 1 \\ 1 & 0\end{array}\right]$ and $A=A^{-1}$, then $x=\ldots \ldots$