Gravitation

The value of acceleration due to gravity (g) becomes $\left(\frac{g}{3}\right)$ at height ' $h$ ' above the earth's surface. If ' R ' is the radius of earth, the height h will be equal to

An object is released from a distance ' $r$ ' from the centre of the earth. The velocity of the object at the time of striking the earth will be ( $R=$ radius of earth, $r>R, g=$ acceleration due to gravity)

The height at which the acceleration due to gravity becomes $\frac{g}{4}$ in terms of $R$ is $[R=$ the radius of the earth $]$

A satellite is revolving round the earth with orbital speed ' $\mathrm{V}_0$ '. If it stops suddenly, the speed with which it will strike the surface of the earth would be ( $\mathrm{V}_{\mathrm{e}}=$ escape velocity of a particle on earth'...

A satellite of mass ' $m$ ' is orbiting the earth of radius ' $R$ ' at height ' $h$ ' from the surface of earth. The total energy of the satellite is ( $\mathrm{g}=$ acceleration due to gravity at the earth's surface)

The period of revolution of planet A around the sun is 8 times that of $B$. The distance of $A$ from the sun is how many times greater than that of $B$ from the sun?