Motion in a Plane PYQs - Last 10 Years
KCET / Physics / Mechanics / 9 recent questions
PhysicsMechanics2017-2026
Practice 9 KCET Physics questions from Motion in a Plane. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
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Physics / Mechanics
2019-2026
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2022-2026
9
Last 10 Years
2017-2026
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3 in last 5 years9 in last 10 years
Last 10 Years Motion in a Plane Questions
Showing 9 of 9 filtered questions.
1Motion In A Plane
Two bodies are projected with the same velocity. If one is projected at an angle of $30^\circ$ and the other at $45^\circ$ to the horizontal, then the ratio of maximum heights attained is
MCQ+1 / -02026
2Motion In A Plane
In the projectile motion of a particle on a level ground, which of the following remains constant with reference to time and position?
MCQ+1 / -02025
3Motion In A Plane
Two objects are projected at an angle \(\theta^{\circ}\) and \(\left(90-\theta^{\circ}\right)\), to the horizontal with the same speed. The ratio of their maximum vertical heights is
MCQ+1 / -02022
4Motion In A Plane
For a projectile motion, the angle between the velocity and acceleration is minimum and acute at
MCQ+1 / -02021
5Motion In A Plane
The maximum range of a gun on horizontal plane is \(16 \mathrm{~km}\). If \(\mathrm{g}=10 \mathrm{~ms}^{-2}\), then muzzle velocity of a shell is
MCQ+1 / -02021
6Motion In A Plane
The trajectory of projectile is
MCQ+1 / -02021
7Motion In A Plane
A particle starts from the origin at \(t=0\) with a velocity of \(10 \hat{\mathbf{j}} \mathrm{ms}^{-1}\) and move in the \(x\)-\(y\) plane with a constant acceleration of \((8 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}) \mathrm{ms}^{-2}\). At an i...
MCQ+1 / -02021
8Motion In A Plane
Rain is falling vertically with a speed of \(12 \mathrm{~ms}^{-1}\). A woman rides a bicycles with a speed of \(12 \mathrm{~ms}^{-1}\) in east to west direction. What is the direction in which she should hold her umbrella?
MCQ+1 / -02020
9Motion In A Plane
The trajectory of a projectile projected from origin is given by the equation \(y=x-\frac{2 x^2}{5}\). The initial velocity of the projectile is
MCQ+1 / -02019
