KcetCurrent ElectricityKCET 2026MCQ+1 / -02026The number of electrons moving per second through the filament of a lamp of $60$ W operating at $120$ V is nearly $(e = 1.6 \times 10^{-19}\text{ C})$ _____________.A$6.2 \times 10^{18}$B$6.2 \times 10^{19}$C$3.1 \times 10^{18}$D$3.1 \times 10^{19}$Check AnswerClear SelectionReveal AnswerShow Explanation
