Kcet
Binomial Theorem
KCET 2023
MCQ+1 / -02023
If \(n\) is even and the middle term in the expansion of \(\left(x^2+\frac{1}{x}\right)^n\) is \(924 x^6\), then \(n\) is equal to
Kcet
KCET 2023
If \(n\) is even and the middle term in the expansion of \(\left(x^2+\frac{1}{x}\right)^n\) is \(924 x^6\), then \(n\) is equal to