KcetBinomial TheoremKCET 2018MCQ+1 / -02018The constant term in the expansion of $\left(x^2-\frac{1}{x^2}\right)^{16}$ isA${ }^{16} \mathrm{C}_8$B${ }^{16} \mathrm{C}_7$C${ }^{18} \mathrm{C}_9$D${ }^{16} C_{10}$Check AnswerClear SelectionReveal AnswerShow Explanation
