KcetIndefinite IntegrationKCET 2021MCQ+1 / -02021\(\int \frac{x^3 \sin \left(\tan ^{-1}\left(x^4\right)\right)}{1+x^8} d x\) is equal to A\(\frac{-\cos \left(\tan ^{-1}\left(x^4\right)\right)}{4}+C\) B\(\frac{\cos \left(\tan ^{-1}\left(x^4\right)\right)}{4}+C\)C\(\frac{-\cos \left(\tan ^{-1}\left(x^3\right)\right)}{3}+C\)D\(\frac{\sin \left(\tan ^{-1}\left(x^4\right)\right)}{4}+C\)Check AnswerClear SelectionReveal AnswerShow Explanation
