KcetIndefinite IntegrationKCET 2025MCQ+1 / -02025$\int \frac{\mathrm{dx}}{\mathrm{x}^2\left(\mathrm{x}^4+1\right)^{3 / 4}}$ equalsA$\left(\frac{x^4+1}{x^4}\right)^{\frac{1}{4}}+c$B $\left(x^4+1\right)^{\frac{1}{4}}+c$C $-\left(\mathrm{x}^4+1\right)^{\frac{1}{4}}+\mathrm{c}$D $-\left(\frac{x^4+1}{x^4}\right)^{\frac{1}{4}}+c$Check AnswerClear SelectionReveal AnswerShow Explanation
