KcetAlternating CurrentKCET 2018MCQ+1 / -02018A 100 W bulb is connected to an AC source of $220 \mathrm{~V}, 50 \mathrm{~Hz}$. Then, the current flowing through the bulb isA$\frac{5}{11} \mathrm{~A}$B$\frac{1}{2} \mathrm{~A}$C2 AD$\frac{3}{4} \mathrm{~A}$Check AnswerClear SelectionReveal AnswerShow Explanation
