KcetAlternating CurrentKCET 2017MCQ+1 / -02017The output of a step down transformers is measured to be 48 V when connected to a 12 W bulb. The value of peak current isA$\frac{1}{\sqrt{2}} \mathrm{~A}$B $\sqrt{2} \mathrm{~A}$C $\frac{1}{2 \sqrt{2}} \mathrm{~A}$D $\frac{1}{4} \mathrm{~A}$Check AnswerClear SelectionReveal AnswerShow Explanation