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Heat And Thermodynamics

JEE Main 2026 (Online) 24th January Evening Shift

MCQ+4 / -12026

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $P_1$ to $P_2$ is $\alpha$ Joule ( $P_1=21.7 \mathrm{~Pa}$ and $\left.P_2=30 \mathrm{~Pa}, \mathrm{C}_v=21 \mathrm{~J} / \mathrm{K} . \mathrm{mol}, R=8.3 \mathrm{~J} / \mathrm{mol} . \mathrm{K}\right)$. The value of $\alpha$ is $\_\_\_\_$ .


JEE Main 2026 (Online) 24th January Evening Shift Physics - Heat and Thermodynamics Question 19 English

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