Electrostatics

$V=\frac{5 q}{4 \pi \varepsilon_o r}$ and $\vec{E}=\frac{5 \sqrt{3} q}{8 \pi \varepsilon_o r^2} \hat{r}$

$V=\frac{5 q}{4 \pi \varepsilon_o r}$ and $\vec{E}=0$

$V=0$ and $\vec{E}=0$

$V=\frac{5 q}{4 \pi \varepsilon_0 r}$ and $\vec{E}=\frac{5 q}{4 \pi \varepsilon_{\mathrm{o}} r^2} \hat{r}$