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Differential Equations

JEE Main 2026 (Online) 21st January Morning Shift

MCQ+4 / -12026

Let $y=y(x)$ be the solution curve of the differential equation $\left(1+x^2\right) \mathrm{d} y+\left(y-\tan ^{-1} x\right) d x=0, y(0)=1$. Then the value of $y(1)$ is :


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