An electrochemical cell is constructed using half cells in the direction of spontaneous change: Fe(OH) 2 (s) + 2e − → Fe(s) + 2OH − (aq) E θ = −0.88 V and AgBr(s) + e − → Ag(s) + Br − (aq) E θ = +0.07 V Which of the following option is correct ?

Jee Main

Electrochemistry

JEE Main 2026 (Online) 2nd April Morning Shift

MCQ+4 / -12026

An electrochemical cell is constructed using half cells in the direction of spontaneous change:

Fe(OH)₂(s) + 2e⁻ → Fe(s) + 2OH⁻(aq) E^θ = −0.88 V

and AgBr(s) + e⁻ → Ag(s) + Br⁻(aq) E^θ = +0.07 V

Which of the following option is correct?