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Electrochemistry

JEE Main 2026 (Online) 21st January Evening Shift

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MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.


$\mathrm{MX}(\mathrm{s}) \rightleftharpoons \mathrm{M}^{+}(\mathrm{aq})+\mathrm{X}^{-}(\mathrm{aq}) ; \quad \mathrm{K}_{\mathrm{sp}}=10^{-10}$


If the standard reduction potential for M+ (aq) + e → M(s) is
$\left(\mathrm{E}_{\mathrm{M}^{+} / \mathrm{M}}^{\ominus}\right)=0.79 \mathrm{~V}$, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $\mathrm{E}_{\mathrm{X}^{-} / \mathrm{MX}(\mathrm{s}) / \mathrm{M}}^{\ominus}$ is ______ mV. (nearest integer)


[Given: $ \dfrac{2.303 RT}{F} = 0.059\ \text{V} $]

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