Jee Main
Electrochemistry
JEE Main 2025 (Online) 8th April Evening Shift
INTEGER+4 / -12025
Consider the following half cell reaction
\(\text{Cr}_2\text{O}_7^{2-} \, (\text{aq}) + 6\text{e}^- + 14\text{H}^+ \, (\text{aq}) \rightarrow 2\text{Cr}^{3+} \, (\text{aq}) + 7\text{H}_2\text{O} \, (\ell)\)
The reaction was conducted with the ratio of \(\frac{[\text{Cr}^{3+}]^2}{[\text{Cr}_2\text{O}_7^{2-}]} = 10^{-6}\). The pH value at which the EMF of the half cell will become zero is __________.
(nearest integer value)
[Given: standard half cell reduction potential \(E^{\circ}_{\text{Cr}_2\text{O}_7^{2-}, \text{H}^+/\text{Cr}^{3+}} = 1.33\, \text{V}\), \(\frac{2.303RT}{F} = 0.059\, \text{V}\).]
