Jee Main
Work Power And Energy
JEE Main 2025 (Online) 24th January Morning Shift
MCQ+4 / -12025
A force $\mathrm{F}=\alpha+\beta \mathrm{x}^2$ acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m . If the constant $\alpha=1 \mathrm{~N}$ then $\beta$ will be
