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Work Power And Energy

JEE Main 2025 (Online) 24th January Morning Shift

MCQ+4 / -12025

A force $\mathrm{F}=\alpha+\beta \mathrm{x}^2$ acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m . If the constant $\alpha=1 \mathrm{~N}$ then $\beta$ will be

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