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Limits Continuity And Differentiability

JEE Main 2025 (Online) 8th April Evening Shift

MCQ+4 / -12025

Given below are two statements:


Statement I: $ \lim\limits_{x \to 0} \left( \frac{\tan^{-1} x + \log_e \sqrt{\frac{1+x}{1-x}} - 2x}{x^5} \right) = \frac{2}{5} $


Statement II: $ \lim\limits_{x \to 1} \left( x^{\frac{2}{1-x}} \right) = \frac{1}{e^2} $


In the light of the above statements, choose the correct answer from the options given below:

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