Jee Main
Limits Continuity And Differentiability
JEE Main 2025 (Online) 8th April Evening Shift
MCQ+4 / -12025
Given below are two statements:
Statement I: $ \lim\limits_{x \to 0} \left( \frac{\tan^{-1} x + \log_e \sqrt{\frac{1+x}{1-x}} - 2x}{x^5} \right) = \frac{2}{5} $
Statement II: $ \lim\limits_{x \to 1} \left( x^{\frac{2}{1-x}} \right) = \frac{1}{e^2} $
In the light of the above statements, choose the correct answer from the options given below:
