Jee Main
Limits Continuity And Differentiability
JEE Main 2025 (Online) 29th January Morning Shift
MCQ+4 / -12025
The value of $\lim \limits_{n \rightarrow \infty}\left(\sum\limits_{k=1}^n \frac{k^3+6 k^2+11 k+5}{(k+3)!}\right)$ is :
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