Jee Main
Ellipse
JEE Main 2025 (Online) 29th January Evening Shift
MCQ+4 / -12025
If $\alpha x+\beta y=109$ is the equation of the chord of the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$, whose mid point is $\left(\frac{5}{2}, \frac{1}{2}\right)$. then $\alpha+\beta$ is equal to :