Jee Main
3d Geometry
JEE Main 2025 (Online) 22nd January Evening Shift
MCQ+4 / -12025
The perpendicular distance, of the line $\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}$ from the point $\mathrm{P}(2,-10,1)$, is :
Jee Main
JEE Main 2025 (Online) 22nd January Evening Shift
The perpendicular distance, of the line $\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}$ from the point $\mathrm{P}(2,-10,1)$, is :