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Rotational Motion

JEE Main 2024 (Online) 31st January Evening Shift

INTEGER+4 / -12024

A body of mass '\(m\)' is projected with a speed '\(u\)' making an angle of \(45^{\circ}\) with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as \(\frac{\sqrt{2} m u^3}{X g}\). The value of '\(X\)' is _________.

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