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Electrostatics

JEE Main 2024 (Online) 8th April Morning Shift

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An electric field, \(\overrightarrow{\mathrm{E}}=\frac{2 \hat{i}+6 \hat{j}+8 \hat{k}}{\sqrt{6}}\) passes through the surface of \(4 \mathrm{~m}^2\) area having unit vector \(\hat{n}=\left(\frac{2 \hat{i}+\hat{j}+\hat{k}}{\sqrt{6}}\right)\). The electric flux for that surface is _________ \(\mathrm{Vm}\).

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