Jee Main
Limits Continuity And Differentiability
JEE Main 2024 (Online) 9th April Evening Shift
MCQ+4 / -12024
\(\lim _\limits{x \rightarrow 0} \frac{e-(1+2 x)^{\frac{1}{2 x}}}{x}\) is equal to
Jee Main
JEE Main 2024 (Online) 9th April Evening Shift
\(\lim _\limits{x \rightarrow 0} \frac{e-(1+2 x)^{\frac{1}{2 x}}}{x}\) is equal to