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Limits Continuity And Differentiability

JEE Main 2024 (Online) 6th April Evening Shift

MCQ+4 / -12024

\(\lim _\limits{n \rightarrow \infty} \frac{\left(1^2-1\right)(n-1)+\left(2^2-2\right)(n-2)+\cdots+\left((n-1)^2-(n-1)\right) \cdot 1}{\left(1^3+2^3+\cdots \cdots+n^3\right)-\left(1^2+2^2+\cdots \cdots+n^2\right)}\) is equal to :

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