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JEE Main 2024 (Online) 9th April Morning Shift

MCQ+4 / -12024

Let \(f(x)=x^2+9, g(x)=\frac{x}{x-9}\) and \(\mathrm{a}=f \circ g(10), \mathrm{b}=g \circ f(3)\). If \(\mathrm{e}\) and \(l\) denote the eccentricity and the length of the latus rectum of the ellipse \(\frac{x^2}{\mathrm{a}}+\frac{y^2}{\mathrm{~b}}=1\), then \(8 \mathrm{e}^2+l^2\) is equal to.

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