Jee Main
3d Geometry
JEE Main 2024 (Online) 30th January Morning Shift
MCQ+4 / -12024
Let \((\alpha, \beta, \gamma)\) be the foot of perpendicular from the point \((1,2,3)\) on the line \(\frac{x+3}{5}=\frac{y-1}{2}=\frac{z+4}{3}\). Then \(19(\alpha+\beta+\gamma)\) is equal to :