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Chemical Equilibrium

JEE Main 2024 (Online) 29th January Morning Shift

INTEGER+4 / -12024

For the reaction \(\mathrm{N}_2 \mathrm{O}_{4(\mathrm{~g})} \rightleftarrows 2 \mathrm{NO}_{2(\mathrm{~g})}, \mathrm{K}_{\mathrm{p}}=0.492 \mathrm{~atm}\) at \(300 \mathrm{~K} . \mathrm{K}_{\mathrm{c}}\) for the reaction at same temperature is _________ \(\times 10^{-2}\).


(Given : \(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\))

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