Simple Harmonic Motion

At a given point of time the value of displacement of a simple harmonic oscillator is given as \(\mathrm{y}=\mathrm{A} \cos \left(30^{\circ}\right)\).
If amplitude is \(40 \mathrm{~cm}\) and kinetic energy at that time is \(200 \mathrm{~J}\), the value of force constant is \(1.0 \times 10^{x} ~\mathrm{Nm}^{-1}\). The value of \(x\) is ____________.