Jee Main
Laws Of Motion
JEE Main 2023 (Online) 15th April Morning Shift
MCQ+4 / -12023
The position vector of a particle related to time $t$ is given by
$\vec{r}=\left(10 t \hat{i}+15 t^{2} \hat{j}+7 \hat{k}\right) m$
The direction of net force experienced by the particle is :
$\vec{r}=\left(10 t \hat{i}+15 t^{2} \hat{j}+7 \hat{k}\right) m$
The direction of net force experienced by the particle is :