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Laws Of Motion

JEE Main 2022 (Online) 30th June Morning Shift

MCQ+4 / -12022

A 2 kg block is pushed against a vertical wall by applying a horizontal force of 50 N. The coefficient of static friction between the block and the wall is 0.5. A force F is also applied on the block vertically upward (as shown in figure). The maximum value of F applied, so that the block does not move upward, will be :


(Given : g = 10 ms\(-\)2)


JEE Main 2022 (Online) 30th June Morning Shift Physics - Laws of Motion Question 72 English

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