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Laws Of Motion

JEE Main 2023 (Online) 1st February Morning Shift

MCQ+4 / -12023

A block of mass \(5 \mathrm{~kg}\) is placed at rest on a table of rough surface. Now, if a force of \(30 \mathrm{~N}\) is applied in the direction parallel to surface of the table, the block slides through a distance of \(50 \mathrm{~m}\) in an interval of time \(10 \mathrm{~s}\). Coefficient of kinetic friction is (given, \(g=10 \mathrm{~ms}^{-2}\)):

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