Jee Main
Electromagnetic Waves
JEE Main 2023 (Online) 11th April Morning Shift
MCQ+4 / -12023
The electric field in an electromagnetic wave is given as
\(\overrightarrow{\mathrm{E}}=20 \sin \omega\left(\mathrm{t}-\frac{x}{\mathrm{c}}\right) \overrightarrow{\mathrm{j}} \mathrm{NC}^{-1}\)
where \(\omega\) and \(c\) are angular frequency and velocity of electromagnetic wave respectively. The energy contained in a volume of \(5 \times 10^{-4} \mathrm{~m}^{3}\) will be
(Given \(\varepsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} / \mathrm{Nm}^{2}\) )
