PracBeeLogin

Jee Main

Electromagnetic Waves

JEE Main 2022 (Online) 30th June Morning Shift

MCQ+4 / -12022

An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5\(\pi\) \(\times\) 103x \(-\) 3\(\pi\) \(\times\) 1011t) Vm\(-\)1


Then, the value of magnetic field amplitude will be :


(Given : speed of light in Vacuum c = 3 \(\times\) 108 ms\(-\)1)

Continue this paper

Similar Electromagnetic Waves PYQs

More practice from this question